Spss Regression

Simple flexurear Regression in SPSS 1. STAT 314 Ten Corvettes amid 1 and 6 years old were randomly selected from last years gross revenue records in Virginia Beach, Virginia. The pursuance entropy were obtained, where x denotes age, in years, and y denotes gross revenue worth, in hundreds of dollars. x y a. b. c. d. e. f. g. h. i. j. k. l. m. 6 125 6 115 6 130 4 160 2 219 5 cl 4 190 5 163 1 260 2 260 graph the data in a turn backplot to determine if there is a possible bank notear relationship. encrypt and interpret the linear correlation coefficient, r. turn back the regression equation for the data.Graph the regression equation and the data points. Identify outliers and potential powerful observations. Compute and interpret the coefficient of determination, r2. give the residuals and raise a residual plot. Decide whether it is reasonable to consider that the assumptions for regression psychoanalysis be met by the shiftings in questions. At the 5% significance level , do the data provide sufficient evidence to conclude that the slope of the population regression line is not 0 and, hence, that age is useful as a predictor of sales damage for Corvettes? Obtain and interpret a 95% confidence musical interval for the slope, ? of the population regression line that relates age to sales worth for Corvettes. Obtain a point estimate for the mean sales price of all 4-year-old Corvettes. Determine a 95% confidence interval for the mean sales price of all 4-year-old Corvettes. Find the predicted sales price of Jack Smiths 4-year-old Corvette. Determine a 95% prediction interval for the sales price of Jack Smiths 4-year-old Corvette. Note that the following steps ar not required for all analysesonly perform the necessary steps to make do your problem. Use the above steps as a guide to the correct SPSS steps. 1.Enter the age value into one uncertain and the corresponding sales price values into another variable (see figure, below). 2. Select Graphs ? L egacy Dialogs ? spread out/Dot (select Simple then click the Define button) with the Y axis of rotation variable (Price) and the X Axis variable (Age) entered (see figures, below). firedog Titles to enter a descriptive rubric for your graph, and click Continue. Click OK. Your output should look similar to the figure below. a. Graph the data in a scatterplot to determine if there is a possible linear relationship. The points seem to follow a somewhat linear pattern with a prejudicial slope. . Select Analyze ? Correlate ? Bivariate (see figure, below). 4. Select Age and Price as the variables, select Pearson as the correlation coefficient, and click OK (see the left wing figure, below). b. Compute and interpret the linear correlation coefficient, r. The correlation coefficient is 0. 9679 (see the right figure, above). This value of r suggests a strong negative linear correlation since the value is negative and close to 1. Since the above value of r suggests a strong negative lin ear correlation, the data points should be clustered closely about a negatively sloping regression line.This is consistent with the graph obtained above. Therefore, since we see a strong negative linear relationship between Age and Price, linear regression analysis can continue. 5. Since we eventually want to predict the price of 4-year-old Corvettes (parts jm), enter the number 4 in the Age variable column of the data window after the last row. Enter a . for the corresponding Price variable value (this lets SPSS know that we want a prediction for this value and not to admit the value in any other computations) (see left figure, below). . Select Analyze ? Regression ? Linear (see right figure, above). 7. Select Price as the dependent variable and Age as the independent variable (see upperleft figure, below). Click Statistics, select Estimates and Confidence Intervals for the regression coefficients, select Model fit to obtain r2, and click Continue (see upper-right figure, below) . Click Plots, select Normal Probability Plot of the residuals, and click Continue (see lower-left figure, below).Click Save, select Unstandardized predicted values, select Unstandardized and Studentized residuals, select Mean (to obtain a confidence intervaloutput in the Data Window) and Individual (to obtain a prediction intervaloutput in the Data Window) at the 95% level (or some(prenominal) level the problem requires), and click Continue (see lower-right figure, below). Click OK. The output from this procedure is extensive and will be shown in parts in the following answers. c. Determine the regression equation for the data. From above, the regression equation is Price = 29160. 1942 (2790. 2913)(Age). 8.From within the output window, double-click on the scatterplot to enter Chart Editor mode. From the Elements menu, select Fit Line at Total. Click the close box. Now your scatterplot displays the linear regression line computed above. Graph the regression equation and the data points. d. e. Identify outliers and potential influential observations. There do not appear to be any points that lie far from the cluster of data points or far from the regression line therefore there atomic number 18 no possible outliers or influential observations. f. Compute and interpret the coefficient of determination, r2. The coefficient of determination is 0. 368 therefore, about 93. 68% of the variation in the price data is explained by age. The regression equation appears to be very useful for making predictions since the value of r 2 is close to 1. 9. The residuals and standardized values (as well as the predicted values, the confidence interval endpoints, and the prediction interval endpoints) can be found in the data window. 10. To create a residual plot, select Graphs ? Legacy Dialogs ? Scatter/Dot (Simple) with the residuals (RES_1) as the Y Axis variable and Age as the X Axis variable. Click Titles to enter Residual Plot as the title for your graph, and click Cont inue.Click OK. Double-click the resulting graph in the output window, select Options ? Y Axis Reference Line, select the Reference Line tab key in the properties window, add position of line 0, and click Apply. Click the close box to exit the chart editor (see left plot, below). 11. To create a studentized residual plot (what the textbook calls a standardized residual plot), select Graphs ? Legacy Dialogs ? Scatter/Dot (Simple) with the studentized residuals (SRES_1) as the Y Axis variable and Age as the X Axis variable. Click Titles to enter Studentized Residual Plot as the title for your graph, and click Continue.Click OK. Double-click the resulting graph in the output window, select Options ? Y Axis Reference Line, select the Reference Line tab in the properties window, add position of line 0, and click Apply. If 2 and/or -2 are in the commit covered by the y-axis, repeat the last steps to add a elongation line at 2 and -2 (see right plot, above) any points that are not betwee n these lines are considered potential outliers. If 3 and/or -3 are in the range covered by the y-axis, repeat the last steps to add a reference line at 3 and -3 any points that are beyond these lines are considered outliers. 2. To assess the normality of the residuals, consult the P-P Plot from the regression output. g. Obtain the residuals and create a residual plot. Decide whether it is reasonable to consider that the assumptions for regression analysis are met by the variables in questions. The residual plot shows a random scatter of the points (independence) with a constant spread (constant variance). The studentized residual plot shows a random scatter of the points (independence) with a constant spread (constant variance) with no values beyond the 2 standard deviation reference lines (no outliers).The normal probability plot of the residuals shows the points close to a diagonal line therefore, the residuals appear to be approximately normally distributed. Thus, the assumption s for regression analysis appear to be met. h. At the 10% significance level, do the data provide sufficient evidence to conclude that the slope of the population regression line is not 0 and, hence, that age is useful as a predictor of sales price for Corvettes? Step 1 Hypotheses H 0 = 0 (Age is not a useful predictor of price. ) H a 0 (Age is a useful predictor of price. ) Step 2 Step 3 Step 4 Significance Level 0. 05 Critical Value(s) and Rejection Region(s) Reject the null hypothesis if p-value ? 0. 05. running play Statistic (choose either the T-test method or the F-test methodnot both) T = 10. 8873, and p-value = 0. 00000448 Step 5 Step 6 F = 118. 5330, and p-value = 0. 00000448 Conclusion Since p-value = 0. 00000448 ? 0. 05, we shall reject the null hypothesis. aver conclusion in words At the = 0. 05 level of significance, there exists enough evidence to conclude that the slope of the population regression line is not secret code and, hence, that age is useful as a predictor of price for Corvettes. . Obtain and interpret a 95% confidence interval for the slope, ? , of the population regression line that relates age to sales price for Corvettes. We are 95% positive(p) that the slope of the true regression line is somewhere between 3381. 2946 and 2199. 2880. In other words, we are 95% confident that for every year older Corvettes get, their average price decreases somewhere between $3,381. 2946 and $2,199. 2880. j. Obtain a point estimate for the mean sales price of all 4-year-old Corvettes. The point estimate (PRE_1) is 17999. 0291 dollars ($17,999. 0291). k.Determine a 95% confidence interval for the mean sales price of all 4-year-old Corvettes. We are 95% confident that the mean sales price of all four-year-old Corvettes is somewhere between $16,958. 4604 (LMCI_1) and $19,039. 5978 (UMCI_1). l. Find the predicted sales price of Jack Smiths selected 4-year-old Corvette. The predicted sales price is 17999. 0291 dollars ($17,999. 0291). m. Dete rmine a 95% prediction interval for the sales price of Jack Smiths 4-year-old Corvette. We are 95% certain that the individual sales price of Jack Smith? s Corvette will be somewhere between $14,552. 9173 (LICI_1) and $21,445. 1410 (UICI_1).